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The Emperor will not judge you by your medals and diplomas but by your scars.
occasional meanderings in physics' brave new world
The Emperor will not judge you by your medals and diplomas but by your scars.
In the $3 \times 3$ case, the nine choices for $F$ give the $9$ elementary matrices. Thus any matrix at all may be expressed as a combination of such Fourier transforms. For example, the circulant permutation $(231)$ uses the three Fourier matrices that sum to
A general $1$-circulant is therefore a combination of three transforms, each of this form. An alternative choice of phases for $(231)$ would have given us
which is a bit more reminiscent of CKM symmetries. Since the tribimaximal mixing matrix may be expressed as a product $F_3 F_2$, one hopes that the CKM matrix is also easily written in terms of a natural transform.
Since the eigenvalues of each basis matrix take the values $(1,1,-1)$, the eigenvalues of the sum are of the form
and the multiplication is given by semidirect product
The examples assume that $d = 3$, but $n$ is fairly arbitrary. How does the three dimensional Fourier transform act on such phased circulants? We may decompose the result into a diagonal and a $1$-circulant, as in
Consider the case where $\mu^a = \mu^c$, reducing the circulant to
where the diagonalisation of the ordinary $1$-circulant permutation is clear, if $\mu^a = \mu^b$. In order to be Hermitian, it is clear that the phases must satisfy $\mu^a = \pm 1$ and $\mu^b = \pm 1$. For example, when $(\mu^a , \mu^b)=(1,-1)$ then the two real eigenvalues for this operator are given byYou are not supposed to notice sexist behavior, and everything in our society is carefully designed to help you understand and accept it as natural and just the way things are and evolution and the battle of the sexes and God's will and girls like pink and boys love trucks and men are better at spatial hoo hah and women are so verbal and boys will be boys and act like a lady and don't be a slut and men can't help themselves and blah blah blah. If you should, by some amazing effort of will and education, manage to pull the curtain aside, there will be a great show of smoke and fire and booming voices declaiming from a huge green glaring disembodied head "pay no attention to that patriarchy behind the curtain!" Because, well, you might notice that it's a humbug.
That is, we assume that the galaxy (at low $z$) is fairly close to us and that the quasar (at high $z$) is very far away. But we do not assume that the distance between the galaxy and the quasar is determined by the pink curve. In fact, the observed filaments connecting quasars and galaxies suggest that the two objects are close together. From the perspective of Earth, it looks like the filament matter travels through cosmic time. If quasars are busy creating galaxies in the early universe, perhaps they are also creating their futures!
which leads to the odd convention of writing, for $d = 3$,
The pentagon formula is given by
which shows that a pentagon has $5$ vertices and $5$ edges. Our favourite associahedron in dimension $3$ is described by
These $M$ matrices work for any polytopes. Another example is the cyclohedron face vector, given by
Note that the usual description of the $M_d$ matrices does not define them as square matrices, but square matrices work fine.
which easily generalises to the $n \times n$ case. Alternatively, with one type of product a natural ternary product on three cubes $A$, $B$ and $C$ is given by
for two parameters $r$ and $\theta$. Under the nonassociative exponential product, $M$ acts on the right of the democratic matrix as a scaling, as in
whereas its left action is of the form
So when $\lambda = r = 1$, the special scale free value of $\theta$ results in a familiar choice for $M$, namely
where $\omega$ is a sixth root of unity. Note that a zero element in a left hand factor results in a totally zero matrix, so the nonassociative product has many zero divisors.
Consider a Koide mass matrix with two real parameters, $r = e^x$ and $\theta$. This may now be expressed in the form
which puts the mass gap between distinct eigenvalues into a simple complex number, $x \pm i \theta$. Note that any base may replace $e$ here, so long as logarithms are taken in that base. Scalar multiplication of the left hand matrix by $\lambda$ results in a rescaling of $\lambda^{2x}$, so for the special value of $x = 1/2$ this nonassociative product preserves scale. Scalar multiplication on the right would not be permitted.